Searched refs:substr (Results 1 – 3 of 3) sorted by relevance
29 attrs[childKey.substr(1)] = jso[childKey]
102 char *strrstr(const char *s, const char *substr) in strrstr() argument107 while ((found = strstr(p, substr))) in strrstr()
242 const f = s => `0${s}`.substr(-2);
Completed in 7 milliseconds