Searched refs:rd1 (Results 1 – 9 of 9) sorted by relevance
| /linux-6.3-rc2/Documentation/translations/zh_CN/scheduler/ |
| A D | sched-energy.rst | 92 RDs: |----rd1----|-----rd2-----|
95 每个根域包含6个CPU。这两个根域在上图中被表示为rd1和rd2。由于pd4与rd1和rd2
98 * rd1->pd: pd0 -> pd4
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| /linux-6.3-rc2/drivers/staging/vt6655/ |
| A D | desc.h | 186 volatile struct vnt_rdes1 rd1; member
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| A D | dpc.c | 129 frame_size = le16_to_cpu(curr_rd->rd1.req_count) in vnt_receive_frame()
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| A D | card.c | 446 pDesc->rd1.req_count = cpu_to_le16(priv->rx_buf_sz); in CARDvSafeResetRx()
454 pDesc->rd1.req_count = cpu_to_le16(priv->rx_buf_sz); in CARDvSafeResetRx()
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| A D | device_main.c | 873 rd->rd1.req_count = cpu_to_le16(priv->rx_buf_sz); in device_alloc_rx_buf()
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| /linux-6.3-rc2/net/wireless/ |
| A D | reg.c | 1334 static int reg_rules_intersect(const struct ieee80211_regdomain *rd1, in reg_rules_intersect() argument
1369 max_bandwidth1 = reg_get_max_bandwidth(rd1, rule1); in reg_rules_intersect()
1497 regdom_intersect(const struct ieee80211_regdomain *rd1, in regdom_intersect() argument
1507 if (!rd1 || !rd2) in regdom_intersect()
1518 for (x = 0; x < rd1->n_reg_rules; x++) { in regdom_intersect()
1519 rule1 = &rd1->reg_rules[x]; in regdom_intersect()
1522 if (!reg_rules_intersect(rd1, rd2, rule1, rule2, in regdom_intersect()
1535 for (x = 0; x < rd1->n_reg_rules; x++) { in regdom_intersect()
1536 rule1 = &rd1->reg_rules[x]; in regdom_intersect()
1539 r = reg_rules_intersect(rd1, rd2, rule1, rule2, in regdom_intersect()
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| /linux-6.3-rc2/Documentation/scheduler/ |
| A D | sched-energy.rst | 104 RDs: |----rd1----|-----rd2-----|
108 containing 6 CPUs. The two root domains are denoted rd1 and rd2 in the
109 above figure. Since pd4 intersects with both rd1 and rd2, it will be
112 * rd1->pd: pd0 -> pd4
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| /linux-6.3-rc2/Documentation/admin-guide/ |
| A D | md.rst | 604 So for a 3 drive array there will be rd0, rd1, rd2.
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| A D | ras.rst | 1017 Ch1 phy rd1, wr1 (0x063f4031): 2 ranks, UDIMMs
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